Assuming chain plate base =plank: 14 ft
500 lb. x 7 ft. = (vertical chainplate load) lbs x 14 ft.
max mast load compression =vertical chainplate load
max mast load compression= 250 lbs.
There is more going on here, but I need spreader information.
> Does anyone have advise on how to calculate mast/sail loads? This is
> actually for a solid wing ice boat, but I think if I can understand
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> Thanks for any assistance,
> Dave
ddinc - 28 Dec 2004 01:48 GMT
If you give me the sail CE height from the ground,
I can add the sail compression load. Is there a forestay?
Height?
> Assuming chain plate base =plank: 14 ft
>
[quoted text clipped - 28 lines]
>> Thanks for any assistance,
>> Dave
Dave Schneider - 30 Dec 2004 12:52 GMT
I forgot to mention that the wing has shrouds and a forestay, probably
around the 8 ft mark. CE is around 6 ft.
> If you give me the sail CE height from the ground,
> I can add the sail compression load. Is there a forestay?
[quoted text clipped - 32 lines]
> >> Thanks for any assistance,
> >> Dave
Hi Dave,
I think your on the right track. The capsize moment is simply the weight
times 1/2 the "beam", but dynamic loads (wind gusts, sharp turns, bumps,
etc.) are more difficult to quantify. On my last wing sail project I
doubled the capsize moment to account for dynamic effects. Crude, but you
have to start somewhere. The next step is to use the beam equation, Stress
= MC/I, to calculate the required mast size and thickness ( I ), for an
assumed stress level. If your building the wing out of composite materials
its a good idea to build some samples, test them to failure, calculate the
failure stress, and use a percentage of this stress ( 50% ) in the beam
equation to calculate the minimum I (moment of inertia) required. SKEN'S
ELEMENTS OF YACHT DESIGN has some examples of the basic process. You can
get more details on my wing sail projects at:
http://www.johnsboatstuff.com/Articles/rigid2.htm .
Good Luck,
John
> Does anyone have advise on how to calculate mast/sail loads? This is
> actually for a solid wing ice boat, but I think if I can understand
[quoted text clipped - 19 lines]
> Thanks for any assistance,
> Dave
Dave Schneider - 30 Dec 2004 13:53 GMT
Thanks John.
I looked at my movement drawings a little more and I think I understand the
static loads. As I said, the mast/wing does have a mechanical advantage
for lifting the hull. Using the lee runner as the radius center, the
capsize moment is the ratio of the hull circumference and the CE
circumference. With pi factored out, the algorithim is:
|
|
|
h |
|
|
+------+------+
| b |
500 * b/sqr(h*h+b*b) (the CE radius is simple trig)
Actually the base in this example is less than b because the movement isn't
actually against the lee runner, but against a line that is tangent to the
hypotenuse of the triangle formed by the rear plank and the front steering
spring board. This omission actually errors on the side of safety so I'm
not going to worry about it.
I'm ok with designing the wing if I know the loads. I purchased a spar
designer that is used for designing airplane wings. The program isn't
perfect for this application because it assumes a cantelevered wing
(unstayed). Only the portion of the wing above the stays is cantelevered.
So now I'm still left with the dynamic loads encountered in a gust. I'm ok
with just doubling the loads if that works.
FYI: here is a web site that I'm co-managing. I'm co-managing only because
I helped instigate the forming of the group, not because I know anything
about wings. :-) My alias in that group is Sllingblade.
http://groups.msn.com/LandsailerandIceboatdesignandconstruction
> Hi Dave,
> I think your on the right track. The capsize moment is simply the weight
[quoted text clipped - 37 lines]
> > Thanks for any assistance,
> > Dave